Base | Representation |
---|---|
bin | 1010000000111011001011… |
… | …0011110010101101011111 |
3 | 1102222122022121011112001012 |
4 | 2200032302303302231133 |
5 | 2420401012240214101 |
6 | 35230214543205435 |
7 | 2214342605043452 |
oct | 240166263625537 |
9 | 42878277145035 |
10 | 11011001101151 |
11 | 356581507a047 |
12 | 129a009ba687b |
13 | 61b44364596c |
14 | 2a0d14651499 |
15 | 14164c3b4bbb |
hex | a03b2cf2b5f |
11011001101151 has 2 divisors, whose sum is σ = 11011001101152. Its totient is φ = 11011001101150.
The previous prime is 11011001101099. The next prime is 11011001101171. The reversal of 11011001101151 is 15110110011011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11011001101151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11011001101171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505500550575 + 5505500550576.
It is an arithmetic number, because the mean of its divisors is an integer number (5505500550576).
Almost surely, 211011001101151 is an apocalyptic number.
11011001101151 is a deficient number, since it is larger than the sum of its proper divisors (1).
11011001101151 is an equidigital number, since it uses as much as digits as its factorization.
11011001101151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5, while the sum is 14.
Adding to 11011001101151 its reverse (15110110011011), we get a palindrome (26121111112162).
The spelling of 11011001101151 in words is "eleven trillion, eleven billion, one million, one hundred one thousand, one hundred fifty-one".
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