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110110012303 is a prime number
BaseRepresentation
bin110011010001100010…
…0010111001110001111
3101112012202102011212211
41212203010113032033
53301001130343203
6122330035411251
710645425443014
oct1464304271617
9345182364784
10110110012303
114277425aa75
121940b753b27
13a4ca237a45
145487a5d70b
152ce6ac8c6d
hex19a311738f

110110012303 has 2 divisors, whose sum is σ = 110110012304. Its totient is φ = 110110012302.

The previous prime is 110110012289. The next prime is 110110012307. The reversal of 110110012303 is 303210011011.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110110012303 is a prime.

It is a super-2 number, since 2×1101100123032 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110110012307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55055006151 + 55055006152.

It is an arithmetic number, because the mean of its divisors is an integer number (55055006152).

Almost surely, 2110110012303 is an apocalyptic number.

110110012303 is a deficient number, since it is larger than the sum of its proper divisors (1).

110110012303 is an equidigital number, since it uses as much as digits as its factorization.

110110012303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 110110012303 its reverse (303210011011), we get a palindrome (413320023314).

The spelling of 110110012303 in words is "one hundred ten billion, one hundred ten million, twelve thousand, three hundred three".