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110111000000083 is a prime number
BaseRepresentation
bin11001000010010100110111…
…000010100111011001010011
3112102212111201220122000201021
4121002110313002213121103
5103413024312000000313
61030104143423020311
732123154141121255
oct3102246702473123
9472774656560637
10110111000000083
11320a28a3a04155
12104242bb13a697
134959565a08594
141d29587c71cd5
15cae38e4db78d
hex6425370a7653

110111000000083 has 2 divisors, whose sum is σ = 110111000000084. Its totient is φ = 110111000000082.

The previous prime is 110111000000041. The next prime is 110111000000161. The reversal of 110111000000083 is 380000000111011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 110111000000083 - 217 = 110110999869011 is a prime.

It is not a weakly prime, because it can be changed into another prime (110111000001083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55055500000041 + 55055500000042.

It is an arithmetic number, because the mean of its divisors is an integer number (55055500000042).

Almost surely, 2110111000000083 is an apocalyptic number.

110111000000083 is a deficient number, since it is larger than the sum of its proper divisors (1).

110111000000083 is an equidigital number, since it uses as much as digits as its factorization.

110111000000083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 16.

Adding to 110111000000083 its reverse (380000000111011), we get a palindrome (490111000111094).

The spelling of 110111000000083 in words is "one hundred ten trillion, one hundred eleven billion, eighty-three", and thus it is an aban number.