Base | Representation |
---|---|
bin | 11001000010010100110111… |
… | …000010100111011001010011 |
3 | 112102212111201220122000201021 |
4 | 121002110313002213121103 |
5 | 103413024312000000313 |
6 | 1030104143423020311 |
7 | 32123154141121255 |
oct | 3102246702473123 |
9 | 472774656560637 |
10 | 110111000000083 |
11 | 320a28a3a04155 |
12 | 104242bb13a697 |
13 | 4959565a08594 |
14 | 1d29587c71cd5 |
15 | cae38e4db78d |
hex | 6425370a7653 |
110111000000083 has 2 divisors, whose sum is σ = 110111000000084. Its totient is φ = 110111000000082.
The previous prime is 110111000000041. The next prime is 110111000000161. The reversal of 110111000000083 is 380000000111011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110111000000083 - 217 = 110110999869011 is a prime.
It is not a weakly prime, because it can be changed into another prime (110111000001083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55055500000041 + 55055500000042.
It is an arithmetic number, because the mean of its divisors is an integer number (55055500000042).
Almost surely, 2110111000000083 is an apocalyptic number.
110111000000083 is a deficient number, since it is larger than the sum of its proper divisors (1).
110111000000083 is an equidigital number, since it uses as much as digits as its factorization.
110111000000083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 16.
Adding to 110111000000083 its reverse (380000000111011), we get a palindrome (490111000111094).
The spelling of 110111000000083 in words is "one hundred ten trillion, one hundred eleven billion, eighty-three", and thus it is an aban number.
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