Base | Representation |
---|---|
bin | 1010000000111011100101… |
… | …0011001101010111000111 |
3 | 1102222122121012002011021112 |
4 | 2200032321103031113013 |
5 | 2420401223130000241 |
6 | 35230233433235235 |
7 | 2214345366501146 |
oct | 240167123152707 |
9 | 42878535064245 |
10 | 11011110000071 |
11 | 3565870599455 |
12 | 129a03a562b1b |
13 | 61b460083aac |
14 | 2a0d24cbb75d |
15 | 141656c261eb |
hex | a03b94cd5c7 |
11011110000071 has 2 divisors, whose sum is σ = 11011110000072. Its totient is φ = 11011110000070.
The previous prime is 11011110000067. The next prime is 11011110000103. The reversal of 11011110000071 is 17000001111011.
11011110000071 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11011110000071 - 22 = 11011110000067 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11011110000001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505555000035 + 5505555000036.
It is an arithmetic number, because the mean of its divisors is an integer number (5505555000036).
Almost surely, 211011110000071 is an apocalyptic number.
11011110000071 is a deficient number, since it is larger than the sum of its proper divisors (1).
11011110000071 is an equidigital number, since it uses as much as digits as its factorization.
11011110000071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7, while the sum is 14.
Adding to 11011110000071 its reverse (17000001111011), we get a palindrome (28011111111082).
The spelling of 11011110000071 in words is "eleven trillion, eleven billion, one hundred ten million, seventy-one", and thus it is an aban number.
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