11011130023 has 2 divisors, whose sum is σ = 11011130024. Its totient is φ = 11011130022.

The previous prime is 11011129951. The next prime is 11011130051. The reversal of 11011130023 is 32003111011.

It is a strong prime.

It is an emirp because it is prime and its reverse (32003111011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11011130023 - 2²⁹ = 10474259111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11011129985 and 11011130012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11011160023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505565011 + 5505565012.

It is an arithmetic number, because the mean of its divisors is an integer number (5505565012).

Almost surely, 2^11011130023 is an apocalyptic number.

11011130023 is a deficient number, since it is larger than the sum of its proper divisors (1).

11011130023 is an equidigital number, since it uses as much as digits as its factorization.

11011130023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 11011130023 its reverse (32003111011), we get a palindrome (43014241034).

The spelling of 11011130023 in words is "eleven billion, eleven million, one hundred thirty thousand, twenty-three".