Base | Representation |
---|---|
bin | 10000000001011111011… |
… | …101111100000001010001 |
3 | 10220021011110221211202002 |
4 | 100001133131330001101 |
5 | 121020040001430223 |
6 | 2201502223403345 |
7 | 142360420501061 |
oct | 20013735740121 |
9 | 3807143854662 |
10 | 1101113311313 |
11 | 394a85838294 |
12 | 1594a0753555 |
13 | 7cab0639a72 |
14 | 3b4192ad3a1 |
15 | 1d9985b5e28 |
hex | 1005f77c051 |
1101113311313 has 2 divisors, whose sum is σ = 1101113311314. Its totient is φ = 1101113311312.
The previous prime is 1101113311297. The next prime is 1101113311349. The reversal of 1101113311313 is 3131133111011.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 986938928704 + 114174382609 = 993448^2 + 337897^2 .
It is a cyclic number.
It is not a de Polignac number, because 1101113311313 - 24 = 1101113311297 is a prime.
It is not a weakly prime, because it can be changed into another prime (1101113311213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550556655656 + 550556655657.
It is an arithmetic number, because the mean of its divisors is an integer number (550556655657).
Almost surely, 21101113311313 is an apocalyptic number.
It is an amenable number.
1101113311313 is a deficient number, since it is larger than the sum of its proper divisors (1).
1101113311313 is an equidigital number, since it uses as much as digits as its factorization.
1101113311313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 20.
Adding to 1101113311313 its reverse (3131133111011), we get a palindrome (4232246422324).
The spelling of 1101113311313 in words is "one trillion, one hundred one billion, one hundred thirteen million, three hundred eleven thousand, three hundred thirteen".
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