Base | Representation |
---|---|
bin | 10000000001011111111… |
… | …111000111111111100111 |
3 | 10220021012002022211121211 |
4 | 100001133333013333213 |
5 | 121020044213323421 |
6 | 2201503134052251 |
7 | 142360554443653 |
oct | 20013777077747 |
9 | 3807162284554 |
10 | 1101122011111 |
11 | 394a8a73a601 |
12 | 1594a364a087 |
13 | 7cab2394885 |
14 | 3b41a4d5a63 |
15 | 1d9992339e1 |
hex | 1005ffc7fe7 |
1101122011111 has 2 divisors, whose sum is σ = 1101122011112. Its totient is φ = 1101122011110.
The previous prime is 1101122011069. The next prime is 1101122011147. The reversal of 1101122011111 is 1111102211011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1101122011111 - 235 = 1066762272743 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1101122011091 and 1101122011100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1101122011511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550561005555 + 550561005556.
It is an arithmetic number, because the mean of its divisors is an integer number (550561005556).
Almost surely, 21101122011111 is an apocalyptic number.
1101122011111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1101122011111 is an equidigital number, since it uses as much as digits as its factorization.
1101122011111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4, while the sum is 13.
Adding to 1101122011111 its reverse (1111102211011), we get a palindrome (2212224222122).
The spelling of 1101122011111 in words is "one trillion, one hundred one billion, one hundred twenty-two million, eleven thousand, one hundred eleven".
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