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11011248317 is a prime number
BaseRepresentation
bin10100100000101001…
…00101000010111101
31001102101121101000202
422100110211002331
5140022334421232
65020345133245
7536604031526
oct122024450275
931371541022
1011011248317
114740620923
12217378a225
131066365464
1476659b84d
15446a62162
hex2905250bd

11011248317 has 2 divisors, whose sum is σ = 11011248318. Its totient is φ = 11011248316.

The previous prime is 11011248233. The next prime is 11011248377. The reversal of 11011248317 is 71384211011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6643228036 + 4368020281 = 81506^2 + 66091^2 .

It is an emirp because it is prime and its reverse (71384211011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11011248317 - 216 = 11011182781 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11011248317.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11011248377) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505624158 + 5505624159.

It is an arithmetic number, because the mean of its divisors is an integer number (5505624159).

Almost surely, 211011248317 is an apocalyptic number.

It is an amenable number.

11011248317 is a deficient number, since it is larger than the sum of its proper divisors (1).

11011248317 is an equidigital number, since it uses as much as digits as its factorization.

11011248317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1344, while the sum is 29.

Adding to 11011248317 its reverse (71384211011), we get a palindrome (82395459328).

The spelling of 11011248317 in words is "eleven billion, eleven million, two hundred forty-eight thousand, three hundred seventeen".