Base | Representation |
---|---|
bin | 110011010001100111… |
… | …1110000111101110101 |
3 | 101112012222001001001122 |
4 | 1212203033300331311 |
5 | 3301002412020313 |
6 | 122330223433325 |
7 | 10645463032256 |
oct | 1464317607565 |
9 | 345188031048 |
10 | 110113001333 |
11 | 42775a11745 |
12 | 19410755845 |
13 | a4caa433ba |
14 | 54881dab2d |
15 | 2ce6eb9708 |
hex | 19a33f0f75 |
110113001333 has 2 divisors, whose sum is σ = 110113001334. Its totient is φ = 110113001332.
The previous prime is 110113001329. The next prime is 110113001359. The reversal of 110113001333 is 333100311011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 89343003409 + 20769997924 = 298903^2 + 144118^2 .
It is a cyclic number.
It is not a de Polignac number, because 110113001333 - 22 = 110113001329 is a prime.
It is a super-2 number, since 2×1101130013332 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110113001633) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55056500666 + 55056500667.
It is an arithmetic number, because the mean of its divisors is an integer number (55056500667).
Almost surely, 2110113001333 is an apocalyptic number.
It is an amenable number.
110113001333 is a deficient number, since it is larger than the sum of its proper divisors (1).
110113001333 is an equidigital number, since it uses as much as digits as its factorization.
110113001333 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 110113001333 its reverse (333100311011), we get a palindrome (443213312344).
The spelling of 110113001333 in words is "one hundred ten billion, one hundred thirteen million, one thousand, three hundred thirty-three".
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