Base | Representation |
---|---|
bin | 1010000000111100010101… |
… | …0110001111010110001111 |
3 | 1102222200010021101222101102 |
4 | 2200033011112033112033 |
5 | 2420402131400334411 |
6 | 35230305453333315 |
7 | 2214353402501522 |
oct | 240170526172617 |
9 | 42880107358342 |
10 | 11011312121231 |
11 | 35659646a0034 |
12 | 129a09619723b |
13 | 61b492c01706 |
14 | 2a0d43a92bb9 |
15 | 14166984dd3b |
hex | a03c558f58f |
11011312121231 has 2 divisors, whose sum is σ = 11011312121232. Its totient is φ = 11011312121230.
The previous prime is 11011312121219. The next prime is 11011312121261. The reversal of 11011312121231 is 13212121311011.
11011312121231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11011312121231 - 214 = 11011312104847 is a prime.
It is a super-2 number, since 2×110113121212312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11011312121261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505656060615 + 5505656060616.
It is an arithmetic number, because the mean of its divisors is an integer number (5505656060616).
Almost surely, 211011312121231 is an apocalyptic number.
11011312121231 is a deficient number, since it is larger than the sum of its proper divisors (1).
11011312121231 is an equidigital number, since it uses as much as digits as its factorization.
11011312121231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 20.
Adding to 11011312121231 its reverse (13212121311011), we get a palindrome (24223433432242).
The spelling of 11011312121231 in words is "eleven trillion, eleven billion, three hundred twelve million, one hundred twenty-one thousand, two hundred thirty-one".
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