Base | Representation |
---|---|
bin | 10100100000101001… |
… | …10101100000101011 |
3 | 1001102101201210112110 |
4 | 22100110311200223 |
5 | 140022344101010 |
6 | 5020350413403 |
7 | 536604432246 |
oct | 122024654053 |
9 | 31371653473 |
10 | 11011315755 |
11 | 4740667560 |
12 | 2173801263 |
13 | 106638a06b |
14 | 7665b825d |
15 | 446a77120 |
hex | 29053582b |
11011315755 has 64 divisors (see below), whose sum is σ = 19384012800. Its totient is φ = 5293411200.
The previous prime is 11011315729. The next prime is 11011315781. The reversal of 11011315755 is 55751311011.
It is an interprime number because it is at equal distance from previous prime (11011315729) and next prime (11011315781).
It is not a de Polignac number, because 11011315755 - 213 = 11011307563 is a prime.
It is a super-2 number, since 2×110113157552 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 16121644 + ... + 16122326.
It is an arithmetic number, because the mean of its divisors is an integer number (302875200).
Almost surely, 211011315755 is an apocalyptic number.
11011315755 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11011315755 is a deficient number, since it is larger than the sum of its proper divisors (8372697045).
11011315755 is a wasteful number, since it uses less digits than its factorization.
11011315755 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1392.
The product of its (nonzero) digits is 2625, while the sum is 30.
Adding to 11011315755 its reverse (55751311011), we get a palindrome (66762626766).
The spelling of 11011315755 in words is "eleven billion, eleven million, three hundred fifteen thousand, seven hundred fifty-five".
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