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110113232023147 is a prime number
BaseRepresentation
bin11001000010010110111100…
…000101000110111001101011
3112102212201111110120112202011
4121002112330011012321223
5103413043344344220042
61030105153115020351
732123263353033163
oct3102267405067153
9472781443515664
10110113232023147
11320a3839916111
121042482273a6b7
13495983026c9a2
141d2971a4875a3
15cae470431a17
hex6425bc146e6b

110113232023147 has 2 divisors, whose sum is σ = 110113232023148. Its totient is φ = 110113232023146.

The previous prime is 110113232023079. The next prime is 110113232023187. The reversal of 110113232023147 is 741320232311011.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 110113232023147 - 27 = 110113232023019 is a prime.

It is not a weakly prime, because it can be changed into another prime (110113232023187) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55056616011573 + 55056616011574.

It is an arithmetic number, because the mean of its divisors is an integer number (55056616011574).

Almost surely, 2110113232023147 is an apocalyptic number.

110113232023147 is a deficient number, since it is larger than the sum of its proper divisors (1).

110113232023147 is an equidigital number, since it uses as much as digits as its factorization.

110113232023147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 31.

Adding to 110113232023147 its reverse (741320232311011), we get a palindrome (851433464334158).

The spelling of 110113232023147 in words is "one hundred ten trillion, one hundred thirteen billion, two hundred thirty-two million, twenty-three thousand, one hundred forty-seven".