Base | Representation |
---|---|
bin | 11001000010010110111100… |
… | …000101000110111001101011 |
3 | 112102212201111110120112202011 |
4 | 121002112330011012321223 |
5 | 103413043344344220042 |
6 | 1030105153115020351 |
7 | 32123263353033163 |
oct | 3102267405067153 |
9 | 472781443515664 |
10 | 110113232023147 |
11 | 320a3839916111 |
12 | 1042482273a6b7 |
13 | 495983026c9a2 |
14 | 1d2971a4875a3 |
15 | cae470431a17 |
hex | 6425bc146e6b |
110113232023147 has 2 divisors, whose sum is σ = 110113232023148. Its totient is φ = 110113232023146.
The previous prime is 110113232023079. The next prime is 110113232023187. The reversal of 110113232023147 is 741320232311011.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110113232023147 - 27 = 110113232023019 is a prime.
It is not a weakly prime, because it can be changed into another prime (110113232023187) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55056616011573 + 55056616011574.
It is an arithmetic number, because the mean of its divisors is an integer number (55056616011574).
Almost surely, 2110113232023147 is an apocalyptic number.
110113232023147 is a deficient number, since it is larger than the sum of its proper divisors (1).
110113232023147 is an equidigital number, since it uses as much as digits as its factorization.
110113232023147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 31.
Adding to 110113232023147 its reverse (741320232311011), we get a palindrome (851433464334158).
The spelling of 110113232023147 in words is "one hundred ten trillion, one hundred thirteen billion, two hundred thirty-two million, twenty-three thousand, one hundred forty-seven".
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