110113400213 has 2 divisors, whose sum is σ = 110113400214. Its totient is φ = 110113400212.

The previous prime is 110113400153. The next prime is 110113400227. The reversal of 110113400213 is 312004311011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 72362076004 + 37751324209 = 269002^2 + 194297^2 .

It is an emirp because it is prime and its reverse (312004311011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110113400213 - 2¹⁰ = 110113399189 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110113400191 and 110113400200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110113400713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55056700106 + 55056700107.

It is an arithmetic number, because the mean of its divisors is an integer number (55056700107).

Almost surely, 2^110113400213 is an apocalyptic number.

It is an amenable number.

110113400213 is a deficient number, since it is larger than the sum of its proper divisors (1).

110113400213 is an equidigital number, since it uses as much as digits as its factorization.

110113400213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 110113400213 its reverse (312004311011), we get a palindrome (422117711224).

The spelling of 110113400213 in words is "one hundred ten billion, one hundred thirteen million, four hundred thousand, two hundred thirteen".