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110117153 is a prime number
BaseRepresentation
bin1101001000001…
…00000100100001
321200012112100002
412210010010201
5211142222103
614532105345
72504660156
oct644040441
9250175302
10110117153
1157181713
1230a65255
1319a767a3
14108a622d
159a02488
hex6904121

110117153 has 2 divisors, whose sum is σ = 110117154. Its totient is φ = 110117152.

The previous prime is 110117129. The next prime is 110117173. The reversal of 110117153 is 351711011.

It is an a-pointer prime, because the next prime (110117173) can be obtained adding 110117153 to its sum of digits (20).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 104509729 + 5607424 = 10223^2 + 2368^2 .

It is a cyclic number.

It is not a de Polignac number, because 110117153 - 210 = 110116129 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (110117173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55058576 + 55058577.

It is an arithmetic number, because the mean of its divisors is an integer number (55058577).

Almost surely, 2110117153 is an apocalyptic number.

It is an amenable number.

110117153 is a deficient number, since it is larger than the sum of its proper divisors (1).

110117153 is an equidigital number, since it uses as much as digits as its factorization.

110117153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 105, while the sum is 20.

The square root of 110117153 is about 10493.6720455711. The cubic root of 110117153 is about 479.3120251158.

Adding to 110117153 its reverse (351711011), we get a palindrome (461828164).

The spelling of 110117153 in words is "one hundred ten million, one hundred seventeen thousand, one hundred fifty-three".