Base | Representation |
---|---|
bin | 10000000001100100101… |
… | …100011100011011000011 |
3 | 10220021101120221220012002 |
4 | 100001210230130123003 |
5 | 121020224424001011 |
6 | 2201515035054215 |
7 | 142362534026441 |
oct | 20014454343303 |
9 | 3807346856162 |
10 | 1101201000131 |
11 | 395020290191 |
12 | 159505ba136b |
13 | 7cac585ca3b |
14 | 3b426bb7b91 |
15 | 1d9a1137c3b |
hex | 10064b1c6c3 |
1101201000131 has 2 divisors, whose sum is σ = 1101201000132. Its totient is φ = 1101201000130.
The previous prime is 1101201000127. The next prime is 1101201000143. The reversal of 1101201000131 is 1310001021011.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (1310001021011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1101201000131 - 22 = 1101201000127 is a prime.
It is a super-2 number, since 2×11012010001312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1101201000181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550600500065 + 550600500066.
It is an arithmetic number, because the mean of its divisors is an integer number (550600500066).
Almost surely, 21101201000131 is an apocalyptic number.
1101201000131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1101201000131 is an equidigital number, since it uses as much as digits as its factorization.
1101201000131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6, while the sum is 11.
Adding to 1101201000131 its reverse (1310001021011), we get a palindrome (2411202021142).
The spelling of 1101201000131 in words is "one trillion, one hundred one billion, two hundred one million, one hundred thirty-one", and thus it is an aban number.
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