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11012012109997 is a prime number
BaseRepresentation
bin1010000000111110111100…
…0100011111000010101101
31102222201221001120002110021
42200033233010133002231
52420410100100004442
635230503140442141
72214406632345223
oct240175704370255
942881831502407
1011012012109997
113566193831a48
12129a2506a9351
1361b574c38952
142a0daca26b13
151416ab01ce67
hexa03ef11f0ad

11012012109997 has 2 divisors, whose sum is σ = 11012012109998. Its totient is φ = 11012012109996.

The previous prime is 11012012109949. The next prime is 11012012110019. The reversal of 11012012109997 is 79990121021011.

11012012109997 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11006131367401 + 5880742596 = 3317549^2 + 76686^2 .

It is a cyclic number.

It is not a de Polignac number, because 11012012109997 - 227 = 11011877892269 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11012012109937) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506006054998 + 5506006054999.

It is an arithmetic number, because the mean of its divisors is an integer number (5506006054999).

Almost surely, 211012012109997 is an apocalyptic number.

It is an amenable number.

11012012109997 is a deficient number, since it is larger than the sum of its proper divisors (1).

11012012109997 is an equidigital number, since it uses as much as digits as its factorization.

11012012109997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20412, while the sum is 43.

The spelling of 11012012109997 in words is "eleven trillion, twelve billion, twelve million, one hundred nine thousand, nine hundred ninety-seven".