11012013251 has 2 divisors, whose sum is σ = 11012013252. Its totient is φ = 11012013250.

The previous prime is 11012013203. The next prime is 11012013253. The reversal of 11012013251 is 15231021011.

It is a strong prime.

It is an emirp because it is prime and its reverse (15231021011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11012013251 is a prime.

It is a Sophie Germain prime.

Together with 11012013253, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11012013253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506006625 + 5506006626.

It is an arithmetic number, because the mean of its divisors is an integer number (5506006626).

Almost surely, 2^11012013251 is an apocalyptic number.

11012013251 is a deficient number, since it is larger than the sum of its proper divisors (1).

11012013251 is an equidigital number, since it uses as much as digits as its factorization.

11012013251 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60, while the sum is 17.

Adding to 11012013251 its reverse (15231021011), we get a palindrome (26243034262).

The spelling of 11012013251 in words is "eleven billion, twelve million, thirteen thousand, two hundred fifty-one".