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110120207 is a prime number
BaseRepresentation
bin1101001000001…
…00110100001111
321200012200112012
412210010310033
5211142321312
614532131435
72505002111
oct644046417
9250180465
10110120207
1157183a3a
1230a66b7b
1319a77cb2
14108a73b1
159a03322
hex6904d0f

110120207 has 2 divisors, whose sum is σ = 110120208. Its totient is φ = 110120206.

The previous prime is 110120173. The next prime is 110120239. The reversal of 110120207 is 702021011.

It is a strong prime.

It is an emirp because it is prime and its reverse (702021011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110120207 - 28 = 110119951 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 110120191 and 110120200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110123207) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55060103 + 55060104.

It is an arithmetic number, because the mean of its divisors is an integer number (55060104).

Almost surely, 2110120207 is an apocalyptic number.

110120207 is a deficient number, since it is larger than the sum of its proper divisors (1).

110120207 is an equidigital number, since it uses as much as digits as its factorization.

110120207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28, while the sum is 14.

The square root of 110120207 is about 10493.8175608308. The cubic root of 110120207 is about 479.3164561705.

Adding to 110120207 its reverse (702021011), we get a palindrome (812141218).

The spelling of 110120207 in words is "one hundred ten million, one hundred twenty thousand, two hundred seven".