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110121021119933 is a prime number
BaseRepresentation
bin11001000010011110001100…
…010110001001110110111101
3112102220110121022010122211022
4121002132030112021312331
5103413210322401314213
61030112522042233525
732123660363205155
oct3102361426116675
9472813538118738
10110121021119933
11320a707663388a
12104262371b58a5
13495a4a1babab5
141d29c58b31765
15cae77916c308
hex64278c589dbd

110121021119933 has 2 divisors, whose sum is σ = 110121021119934. Its totient is φ = 110121021119932.

The previous prime is 110121021119729. The next prime is 110121021120083. The reversal of 110121021119933 is 339911120121011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 89804393404324 + 20316627715609 = 9476518^2 + 4507397^2 .

It is a cyclic number.

It is not a de Polignac number, because 110121021119933 - 242 = 105722974608829 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110121021119893 and 110121021119902.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110121021115933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55060510559966 + 55060510559967.

It is an arithmetic number, because the mean of its divisors is an integer number (55060510559967).

Almost surely, 2110121021119933 is an apocalyptic number.

It is an amenable number.

110121021119933 is a deficient number, since it is larger than the sum of its proper divisors (1).

110121021119933 is an equidigital number, since it uses as much as digits as its factorization.

110121021119933 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2916, while the sum is 35.

The spelling of 110121021119933 in words is "one hundred ten trillion, one hundred twenty-one billion, twenty-one million, one hundred nineteen thousand, nine hundred thirty-three".