Base | Representation |
---|---|
bin | 1010000000111111010011… |
… | …1010101011000101110111 |
3 | 1102222202011220010122022001 |
4 | 2200033310322223011313 |
5 | 2420410300202414312 |
6 | 35230521003120131 |
7 | 2214412233200353 |
oct | 240176472530567 |
9 | 42882156118261 |
10 | 11012110201207 |
11 | 356623413a365 |
12 | 129a279513047 |
13 | 61b58c36169b |
14 | 2a0dbba7c463 |
15 | 1416b4947057 |
hex | a03f4eab177 |
11012110201207 has 2 divisors, whose sum is σ = 11012110201208. Its totient is φ = 11012110201206.
The previous prime is 11012110201181. The next prime is 11012110201231. The reversal of 11012110201207 is 70210201121011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11012110201207 - 235 = 10977750462839 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11012110201237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506055100603 + 5506055100604.
It is an arithmetic number, because the mean of its divisors is an integer number (5506055100604).
Almost surely, 211012110201207 is an apocalyptic number.
11012110201207 is a deficient number, since it is larger than the sum of its proper divisors (1).
11012110201207 is an equidigital number, since it uses as much as digits as its factorization.
11012110201207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 19.
Adding to 11012110201207 its reverse (70210201121011), we get a palindrome (81222311322218).
The spelling of 11012110201207 in words is "eleven trillion, twelve billion, one hundred ten million, two hundred one thousand, two hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •