Base | Representation |
---|---|
bin | 10000000001100101010… |
… | …101000100111001000011 |
3 | 10220021102100000001022211 |
4 | 100001211111010321003 |
5 | 121020240140323101 |
6 | 2201520055242551 |
7 | 142363023411436 |
oct | 20014525047103 |
9 | 3807370001284 |
10 | 1101211651651 |
11 | 3950262a58a1 |
12 | 159509679457 |
13 | 7cac7b1c007 |
14 | 3b42838b81d |
15 | 1d9a203dc51 |
hex | 10065544e43 |
1101211651651 has 2 divisors, whose sum is σ = 1101211651652. Its totient is φ = 1101211651650.
The previous prime is 1101211651607. The next prime is 1101211651669. The reversal of 1101211651651 is 1561561121011.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (1561561121011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1101211651651 - 213 = 1101211643459 is a prime.
It is not a weakly prime, because it can be changed into another prime (1101211651691) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550605825825 + 550605825826.
It is an arithmetic number, because the mean of its divisors is an integer number (550605825826).
Almost surely, 21101211651651 is an apocalyptic number.
1101211651651 is a deficient number, since it is larger than the sum of its proper divisors (1).
1101211651651 is an equidigital number, since it uses as much as digits as its factorization.
1101211651651 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1800, while the sum is 31.
Adding to 1101211651651 its reverse (1561561121011), we get a palindrome (2662772772662).
The spelling of 1101211651651 in words is "one trillion, one hundred one billion, two hundred eleven million, six hundred fifty-one thousand, six hundred fifty-one".
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