Base | Representation |
---|---|
bin | 1010000000111111010110… |
… | …0110001010011011001011 |
3 | 1102222202012200120211212222 |
4 | 2200033311212022123023 |
5 | 2420410311112223424 |
6 | 35230522051324255 |
7 | 2214412432122146 |
oct | 240176546123313 |
9 | 42882180524788 |
10 | 11012121601739 |
11 | 356623a616795 |
12 | 129a2812b068b |
13 | 61b59182386b |
14 | 2a0dbd3a905d |
15 | 1416b5949e5e |
hex | a03f598a6cb |
11012121601739 has 2 divisors, whose sum is σ = 11012121601740. Its totient is φ = 11012121601738.
The previous prime is 11012121601727. The next prime is 11012121601763. The reversal of 11012121601739 is 93710612121011.
11012121601739 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11012121601739 - 236 = 10943402125003 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11012121601699 and 11012121601708.
It is not a weakly prime, because it can be changed into another prime (11012121601339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506060800869 + 5506060800870.
It is an arithmetic number, because the mean of its divisors is an integer number (5506060800870).
Almost surely, 211012121601739 is an apocalyptic number.
11012121601739 is a deficient number, since it is larger than the sum of its proper divisors (1).
11012121601739 is an equidigital number, since it uses as much as digits as its factorization.
11012121601739 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4536, while the sum is 35.
The spelling of 11012121601739 in words is "eleven trillion, twelve billion, one hundred twenty-one million, six hundred one thousand, seven hundred thirty-nine".
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