Base | Representation |
---|---|
bin | 1010000000111111010110… |
… | …0110001010011010111111 |
3 | 1102222202012200120211212112 |
4 | 2200033311212022122333 |
5 | 2420410311112223402 |
6 | 35230522051324235 |
7 | 2214412432122131 |
oct | 240176546123277 |
9 | 42882180524775 |
10 | 11012121601727 |
11 | 356623a616784 |
12 | 129a2812b067b |
13 | 61b59182385c |
14 | 2a0dbd3a9051 |
15 | 1416b5949e52 |
hex | a03f598a6bf |
11012121601727 has 2 divisors, whose sum is σ = 11012121601728. Its totient is φ = 11012121601726.
The previous prime is 11012121601603. The next prime is 11012121601739. The reversal of 11012121601727 is 72710612121011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11012121601727 - 226 = 11012054492863 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11012121601693 and 11012121601702.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11012121604727) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506060800863 + 5506060800864.
It is an arithmetic number, because the mean of its divisors is an integer number (5506060800864).
Almost surely, 211012121601727 is an apocalyptic number.
11012121601727 is a deficient number, since it is larger than the sum of its proper divisors (1).
11012121601727 is an equidigital number, since it uses as much as digits as its factorization.
11012121601727 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2352, while the sum is 32.
Adding to 11012121601727 its reverse (72710612121011), we get a palindrome (83722733722738).
The spelling of 11012121601727 in words is "eleven trillion, twelve billion, one hundred twenty-one million, six hundred one thousand, seven hundred twenty-seven".
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