Base | Representation |
---|---|
bin | 11001000010011110011000… |
… | …001101001111111100101011 |
3 | 112102220111010011120111212012 |
4 | 121002132120031033330223 |
5 | 103413211224322042141 |
6 | 1030112553511310135 |
7 | 32123665330464362 |
oct | 3102363015177453 |
9 | 472814104514765 |
10 | 110121220112171 |
11 | 320a7168998684 |
12 | 1042629197b34b |
13 | 495a5041a2498 |
14 | 1d29c773307d9 |
15 | cae78b877ceb |
hex | 64279834ff2b |
110121220112171 has 2 divisors, whose sum is σ = 110121220112172. Its totient is φ = 110121220112170.
The previous prime is 110121220112143. The next prime is 110121220112203. The reversal of 110121220112171 is 171211022121011.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110121220112171 is a prime.
It is not a weakly prime, because it can be changed into another prime (110121220112131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55060610056085 + 55060610056086.
It is an arithmetic number, because the mean of its divisors is an integer number (55060610056086).
Almost surely, 2110121220112171 is an apocalyptic number.
110121220112171 is a deficient number, since it is larger than the sum of its proper divisors (1).
110121220112171 is an equidigital number, since it uses as much as digits as its factorization.
110121220112171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 23.
Adding to 110121220112171 its reverse (171211022121011), we get a palindrome (281332242233182).
The spelling of 110121220112171 in words is "one hundred ten trillion, one hundred twenty-one billion, two hundred twenty million, one hundred twelve thousand, one hundred seventy-one".
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