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1101212211133 is a prime number
BaseRepresentation
bin10000000001100101010…
…111001101011110111101
310220021102101001110210101
4100001211113031132331
5121020240311224013
62201520115241101
7142363031231536
oct20014527153675
93807371043711
101101212211133
11395026648181
121595098a9191
137cac7c86878
143b42849568d
151d9a20ee8dd
hex100655cd7bd

1101212211133 has 2 divisors, whose sum is σ = 1101212211134. Its totient is φ = 1101212211132.

The previous prime is 1101212211103. The next prime is 1101212211157. The reversal of 1101212211133 is 3311122121011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 580890914244 + 520321296889 = 762162^2 + 721333^2 .

It is an emirp because it is prime and its reverse (3311122121011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1101212211133 - 213 = 1101212202941 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1101212211133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1101212211103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550606105566 + 550606105567.

It is an arithmetic number, because the mean of its divisors is an integer number (550606105567).

Almost surely, 21101212211133 is an apocalyptic number.

It is an amenable number.

1101212211133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1101212211133 is an equidigital number, since it uses as much as digits as its factorization.

1101212211133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 1101212211133 its reverse (3311122121011), we get a palindrome (4412334332144).

The spelling of 1101212211133 in words is "one trillion, one hundred one billion, two hundred twelve million, two hundred eleven thousand, one hundred thirty-three".