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110122000219993 is a prime number
BaseRepresentation
bin11001000010011111000110…
…101101000111111101011001
3112102220120010112111002121111
4121002133012231013331121
5103413214324024014433
61030113203135540321
732124023552341246
oct3102370655077531
9472816115432544
10110122000219993
11320a7529282193
121042646b08a6a1
13495a5c99ac048
141d29d0cb9c5cd
15cae7d50c0dcd
hex6427c6b47f59

110122000219993 has 2 divisors, whose sum is σ = 110122000219994. Its totient is φ = 110122000219992.

The previous prime is 110122000219969. The next prime is 110122000220017. The reversal of 110122000219993 is 399912000221011.

It is a balanced prime because it is at equal distance from previous prime (110122000219969) and next prime (110122000220017).

It can be written as a sum of positive squares in only one way, i.e., 97806027634249 + 12315972585744 = 9889693^2 + 3509412^2 .

It is an emirp because it is prime and its reverse (399912000221011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110122000219993 - 237 = 109984561266521 is a prime.

It is not a weakly prime, because it can be changed into another prime (110122000219963) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55061000109996 + 55061000109997.

It is an arithmetic number, because the mean of its divisors is an integer number (55061000109997).

Almost surely, 2110122000219993 is an apocalyptic number.

It is an amenable number.

110122000219993 is a deficient number, since it is larger than the sum of its proper divisors (1).

110122000219993 is an equidigital number, since it uses as much as digits as its factorization.

110122000219993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17496, while the sum is 40.

The spelling of 110122000219993 in words is "one hundred ten trillion, one hundred twenty-two billion, two hundred nineteen thousand, nine hundred ninety-three".