Base | Representation |
---|---|
bin | 110011010001111001… |
… | …0001011000011011001 |
3 | 101112020121000021211101 |
4 | 1212203302023003121 |
5 | 3301012214133311 |
6 | 122331145031401 |
7 | 10645632510022 |
oct | 1464362130331 |
9 | 345217007741 |
10 | 110122021081 |
11 | 42780012386 |
12 | 19413785561 |
13 | a4cc880a27 |
14 | 54894a7c49 |
15 | 2ce7b9bec1 |
hex | 19a3c8b0d9 |
110122021081 has 2 divisors, whose sum is σ = 110122021082. Its totient is φ = 110122021080.
The previous prime is 110122021049. The next prime is 110122021111. The reversal of 110122021081 is 180120221011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 90189099225 + 19932921856 = 300315^2 + 141184^2 .
It is a cyclic number.
It is not a de Polignac number, because 110122021081 - 25 = 110122021049 is a prime.
It is a super-2 number, since 2×1101220210812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (110122021981) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55061010540 + 55061010541.
It is an arithmetic number, because the mean of its divisors is an integer number (55061010541).
Almost surely, 2110122021081 is an apocalyptic number.
It is an amenable number.
110122021081 is a deficient number, since it is larger than the sum of its proper divisors (1).
110122021081 is an equidigital number, since it uses as much as digits as its factorization.
110122021081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 19.
Adding to 110122021081 its reverse (180120221011), we get a palindrome (290242242092).
The spelling of 110122021081 in words is "one hundred ten billion, one hundred twenty-two million, twenty-one thousand, eighty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.096 sec. • engine limits •