Base | Representation |
---|---|
bin | 1010000000111111101011… |
… | …0111011100111010000101 |
3 | 1102222202102211221221220101 |
4 | 2200033322313130322011 |
5 | 2420411001231114343 |
6 | 35230534530404101 |
7 | 2214414554506231 |
oct | 240177267347205 |
9 | 42882384857811 |
10 | 11012210019973 |
11 | 3566285517708 |
12 | 129a2a6a30631 |
13 | 61b5a6c40846 |
14 | 2a0dcb0235c1 |
15 | 1416bd5b2e4d |
hex | a03faddce85 |
11012210019973 has 2 divisors, whose sum is σ = 11012210019974. Its totient is φ = 11012210019972.
The previous prime is 11012210019929. The next prime is 11012210020003. The reversal of 11012210019973 is 37991001221011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10461233390689 + 550976629284 = 3234383^2 + 742278^2 .
It is an emirp because it is prime and its reverse (37991001221011) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11012210019973 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11012210919973) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506105009986 + 5506105009987.
It is an arithmetic number, because the mean of its divisors is an integer number (5506105009987).
Almost surely, 211012210019973 is an apocalyptic number.
It is an amenable number.
11012210019973 is a deficient number, since it is larger than the sum of its proper divisors (1).
11012210019973 is an equidigital number, since it uses as much as digits as its factorization.
11012210019973 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6804, while the sum is 37.
The spelling of 11012210019973 in words is "eleven trillion, twelve billion, two hundred ten million, nineteen thousand, nine hundred seventy-three".
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