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11012210192807 is a prime number
BaseRepresentation
bin1010000000111111101011…
…1000000111000110100111
31102222202102212021201222122
42200033322320013012213
52420411001302132212
635230534534220155
72214414556126145
oct240177270070647
942882385251878
1011012210192807
11356628562554a
12129a2a6ab465b
1361b5a6ca1405
142a0dcb06a595
151416bd5e9272
hexa03fae071a7

11012210192807 has 2 divisors, whose sum is σ = 11012210192808. Its totient is φ = 11012210192806.

The previous prime is 11012210192743. The next prime is 11012210192827. The reversal of 11012210192807 is 70829101221011.

11012210192807 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11012210192807 - 26 = 11012210192743 is a prime.

It is a super-2 number, since 2×110122101928072 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11012210192827) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506105096403 + 5506105096404.

It is an arithmetic number, because the mean of its divisors is an integer number (5506105096404).

Almost surely, 211012210192807 is an apocalyptic number.

11012210192807 is a deficient number, since it is larger than the sum of its proper divisors (1).

11012210192807 is an equidigital number, since it uses as much as digits as its factorization.

11012210192807 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4032, while the sum is 35.

The spelling of 11012210192807 in words is "eleven trillion, twelve billion, two hundred ten million, one hundred ninety-two thousand, eight hundred seven".