Base | Representation |
---|---|
bin | 10000000001100101111… |
… | …001111000011110111111 |
3 | 10220021110000011020120222 |
4 | 100001211321320132333 |
5 | 121020300123101114 |
6 | 2201521042131555 |
7 | 142363201415261 |
oct | 20014571703677 |
9 | 3807400136528 |
10 | 1101221300159 |
11 | 395030795972 |
12 | 159510950bbb |
13 | 7cac9b198a6 |
14 | 3b42977db31 |
15 | 1d9a2ce798e |
hex | 10065e787bf |
1101221300159 has 2 divisors, whose sum is σ = 1101221300160. Its totient is φ = 1101221300158.
The previous prime is 1101221300119. The next prime is 1101221300209. The reversal of 1101221300159 is 9510031221011.
It is a weak prime.
It is an emirp because it is prime and its reverse (9510031221011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1101221300159 - 232 = 1096926332863 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1101221300119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550610650079 + 550610650080.
It is an arithmetic number, because the mean of its divisors is an integer number (550610650080).
Almost surely, 21101221300159 is an apocalyptic number.
1101221300159 is a deficient number, since it is larger than the sum of its proper divisors (1).
1101221300159 is an equidigital number, since it uses as much as digits as its factorization.
1101221300159 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 26.
The spelling of 1101221300159 in words is "one trillion, one hundred one billion, two hundred twenty-one million, three hundred thousand, one hundred fifty-nine".
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