Base | Representation |
---|---|
bin | 10100100000110000… |
… | …10000101001011101 |
3 | 1001102110102101210101 |
4 | 22100120100221131 |
5 | 140023111311331 |
6 | 5020421541101 |
7 | 536615161153 |
oct | 122030205135 |
9 | 31373371711 |
10 | 11012213341 |
11 | 474111a968 |
12 | 2173b74791 |
13 | 106661278c |
14 | 76676d3d3 |
15 | 446ba3061 |
hex | 290610a5d |
11012213341 has 2 divisors, whose sum is σ = 11012213342. Its totient is φ = 11012213340.
The previous prime is 11012213281. The next prime is 11012213357. The reversal of 11012213341 is 14331221011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9061136100 + 1951077241 = 95190^2 + 44171^2 .
It is a cyclic number.
It is not a de Polignac number, because 11012213341 - 27 = 11012213213 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11012213041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506106670 + 5506106671.
It is an arithmetic number, because the mean of its divisors is an integer number (5506106671).
Almost surely, 211012213341 is an apocalyptic number.
It is an amenable number.
11012213341 is a deficient number, since it is larger than the sum of its proper divisors (1).
11012213341 is an equidigital number, since it uses as much as digits as its factorization.
11012213341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 11012213341 its reverse (14331221011), we get a palindrome (25343434352).
The spelling of 11012213341 in words is "eleven billion, twelve million, two hundred thirteen thousand, three hundred forty-one".
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