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110122209997 is a prime number
BaseRepresentation
bin110011010001111001…
…0111001001011001101
3101112020121100212222021
41212203302321023031
53301012241204442
6122331153050141
710645634224552
oct1464362711315
9345217325867
10110122209997
1142780131308
1219413856951
13a4cc918a07
145489516a29
152ce7bd7e67
hex19a3cb92cd

110122209997 has 2 divisors, whose sum is σ = 110122209998. Its totient is φ = 110122209996.

The previous prime is 110122209971. The next prime is 110122210027. The reversal of 110122209997 is 799902221011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 106055086921 + 4067123076 = 325661^2 + 63774^2 .

It is an emirp because it is prime and its reverse (799902221011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110122209997 - 215 = 110122177229 is a prime.

It is a super-2 number, since 2×1101222099972 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110122209917) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55061104998 + 55061104999.

It is an arithmetic number, because the mean of its divisors is an integer number (55061104999).

Almost surely, 2110122209997 is an apocalyptic number.

It is an amenable number.

110122209997 is a deficient number, since it is larger than the sum of its proper divisors (1).

110122209997 is an equidigital number, since it uses as much as digits as its factorization.

110122209997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40824, while the sum is 43.

The spelling of 110122209997 in words is "one hundred ten billion, one hundred twenty-two million, two hundred nine thousand, nine hundred ninety-seven".