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11012302003405 = 54395016994079
BaseRepresentation
bin1010000001000000000001…
…0110010101110011001101
31102222202200021001012110011
42200100000112111303031
52420411143303102110
635230552014113221
72214420052402423
oct240200026256315
942882607035404
1011012302003405
11356632243317a
12129a3117ab811
1361b5c0008501
142a0dd9329113
151416c66d248a
hexa0400595ccd

11012302003405 has 8 divisors (see below), whose sum is σ = 13244864371200. Its totient is φ = 8789773624656.

The previous prime is 11012302003397. The next prime is 11012302003433. The reversal of 11012302003405 is 50430020321011.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11012302003405 - 23 = 11012302003397 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2508494845 + ... + 2508499234.

It is an arithmetic number, because the mean of its divisors is an integer number (1655608046400).

Almost surely, 211012302003405 is an apocalyptic number.

It is an amenable number.

11012302003405 is a deficient number, since it is larger than the sum of its proper divisors (2232562367795).

11012302003405 is an equidigital number, since it uses as much as digits as its factorization.

11012302003405 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5016994523.

The product of its (nonzero) digits is 720, while the sum is 22.

Adding to 11012302003405 its reverse (50430020321011), we get a palindrome (61442322324416).

The spelling of 11012302003405 in words is "eleven trillion, twelve billion, three hundred two million, three thousand, four hundred five".

Divisors: 1 5 439 2195 5016994079 25084970395 2202460400681 11012302003405