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1101243340073 is a prime number
BaseRepresentation
bin10000000001100111001…
…101111101010100101001
310220021111112121222200002
4100001213031331110221
5121020321243340243
62201523150352345
7142363556641502
oct20014715752451
93807445558602
101101243340073
11395042179878
121595181bb6b5
137cb01565666
143b42c679ba9
151d9a4beceb8
hex1006737d529

1101243340073 has 2 divisors, whose sum is σ = 1101243340074. Its totient is φ = 1101243340072.

The previous prime is 1101243340003. The next prime is 1101243340157. The reversal of 1101243340073 is 3700433421011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1064006691049 + 37236649024 = 1031507^2 + 192968^2 .

It is an emirp because it is prime and its reverse (3700433421011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1101243340073 - 224 = 1101226562857 is a prime.

It is not a weakly prime, because it can be changed into another prime (1101243340003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550621670036 + 550621670037.

It is an arithmetic number, because the mean of its divisors is an integer number (550621670037).

Almost surely, 21101243340073 is an apocalyptic number.

It is an amenable number.

1101243340073 is a deficient number, since it is larger than the sum of its proper divisors (1).

1101243340073 is an equidigital number, since it uses as much as digits as its factorization.

1101243340073 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 29.

Adding to 1101243340073 its reverse (3700433421011), we get a palindrome (4801676761084).

The spelling of 1101243340073 in words is "one trillion, one hundred one billion, two hundred forty-three million, three hundred forty thousand, seventy-three".