Base | Representation |
---|---|
bin | 10000000001100111001… |
… | …101111101010101111101 |
3 | 10220021111112121222210012 |
4 | 100001213031331111331 |
5 | 121020321243341112 |
6 | 2201523150353005 |
7 | 142363556641652 |
oct | 20014715752575 |
9 | 3807445558705 |
10 | 1101243340157 |
11 | 395042179944 |
12 | 1595181bb765 |
13 | 7cb015656cc |
14 | 3b42c679c29 |
15 | 1d9a4bed022 |
hex | 1006737d57d |
1101243340157 has 2 divisors, whose sum is σ = 1101243340158. Its totient is φ = 1101243340156.
The previous prime is 1101243340073. The next prime is 1101243340213. The reversal of 1101243340157 is 7510433421011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1098092314201 + 3151025956 = 1047899^2 + 56134^2 .
It is a cyclic number.
It is not a de Polignac number, because 1101243340157 - 236 = 1032523863421 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1101243540157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550621670078 + 550621670079.
It is an arithmetic number, because the mean of its divisors is an integer number (550621670079).
Almost surely, 21101243340157 is an apocalyptic number.
It is an amenable number.
1101243340157 is a deficient number, since it is larger than the sum of its proper divisors (1).
1101243340157 is an equidigital number, since it uses as much as digits as its factorization.
1101243340157 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10080, while the sum is 32.
Adding to 1101243340157 its reverse (7510433421011), we get a palindrome (8611676761168).
The spelling of 1101243340157 in words is "one trillion, one hundred one billion, two hundred forty-three million, three hundred forty thousand, one hundred fifty-seven".
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