Base | Representation |
---|---|
bin | 10000000001101010100… |
… | …110111111001101111011 |
3 | 10220021122111200110012121 |
4 | 100001222212333031323 |
5 | 121020430324424313 |
6 | 2201532542022111 |
7 | 142365150345361 |
oct | 20015246771573 |
9 | 3807574613177 |
10 | 1101300233083 |
11 | 3950712a8396 |
12 | 159533277937 |
13 | 7cb1029536b |
14 | 3b436049631 |
15 | 1d9a9bda28d |
hex | 1006a9bf37b |
1101300233083 has 2 divisors, whose sum is σ = 1101300233084. Its totient is φ = 1101300233082.
The previous prime is 1101300233063. The next prime is 1101300233123. The reversal of 1101300233083 is 3803320031011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1101300233083 - 217 = 1101300102011 is a prime.
It is not a weakly prime, because it can be changed into another prime (1101300233023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550650116541 + 550650116542.
It is an arithmetic number, because the mean of its divisors is an integer number (550650116542).
Almost surely, 21101300233083 is an apocalyptic number.
1101300233083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1101300233083 is an equidigital number, since it uses as much as digits as its factorization.
1101300233083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 1101300233083 its reverse (3803320031011), we get a palindrome (4904620264094).
The spelling of 1101300233083 in words is "one trillion, one hundred one billion, three hundred million, two hundred thirty-three thousand, eighty-three".
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