Search a number
-
+
11013012110414 = 25506506055207
BaseRepresentation
bin1010000001000010101010…
…1011001011110001001110
31102222211111202020101010202
42200100222223023301032
52420414122100013124
635231150302133502
72214443464250306
oct240205253136116
942884452211122
1011013012110414
113566657256076
12129a48b581292
1361b6a4176082
142a1065774606
15141718bee5ae
hexa042aacbc4e

11013012110414 has 4 divisors (see below), whose sum is σ = 16519518165624. Its totient is φ = 5506506055206.

The previous prime is 11013012110389. The next prime is 11013012110423. The reversal of 11013012110414 is 41401121031011.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×110130121104142 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2753253027602 + ... + 2753253027605.

It is an arithmetic number, because the mean of its divisors is an integer number (4129879541406).

Almost surely, 211013012110414 is an apocalyptic number.

11013012110414 is a deficient number, since it is larger than the sum of its proper divisors (5506506055210).

11013012110414 is an equidigital number, since it uses as much as digits as its factorization.

11013012110414 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5506506055209.

The product of its (nonzero) digits is 96, while the sum is 20.

Adding to 11013012110414 its reverse (41401121031011), we get a palindrome (52414133141425).

The spelling of 11013012110414 in words is "eleven trillion, thirteen billion, twelve million, one hundred ten thousand, four hundred fourteen".

Divisors: 1 2 5506506055207 11013012110414