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1101302013041 is a prime number
BaseRepresentation
bin10000000001101010101…
…101110001110001110001
310220021122122000212211222
4100001222231301301301
5121020431303404131
62201533044114425
7142365201440636
oct20015255616161
93807578025758
101101302013041
1139507230372a
12159533995a15
137cb107695a9
143b43639018d
151d9a9e3c87b
hex1006ab71c71

1101302013041 has 2 divisors, whose sum is σ = 1101302013042. Its totient is φ = 1101302013040.

The previous prime is 1101302013029. The next prime is 1101302013061. The reversal of 1101302013041 is 1403102031011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 873888432400 + 227413580641 = 934820^2 + 476879^2 .

It is a cyclic number.

It is not a de Polignac number, because 1101302013041 - 26 = 1101302012977 is a prime.

It is a super-2 number, since 2×11013020130412 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1101302013061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550651006520 + 550651006521.

It is an arithmetic number, because the mean of its divisors is an integer number (550651006521).

Almost surely, 21101302013041 is an apocalyptic number.

It is an amenable number.

1101302013041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1101302013041 is an equidigital number, since it uses as much as digits as its factorization.

1101302013041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1101302013041 its reverse (1403102031011), we get a palindrome (2504404044052).

The spelling of 1101302013041 in words is "one trillion, one hundred one billion, three hundred two million, thirteen thousand, forty-one".