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1101302013029 is a prime number
BaseRepresentation
bin10000000001101010101…
…101110001110001100101
310220021122122000212211112
4100001222231301301211
5121020431303404104
62201533044114405
7142365201440621
oct20015255616145
93807578025745
101101302013029
11395072303719
12159533995a05
137cb1076959a
143b436390181
151d9a9e3c86e
hex1006ab71c65

1101302013029 has 2 divisors, whose sum is σ = 1101302013030. Its totient is φ = 1101302013028.

The previous prime is 1101302012999. The next prime is 1101302013041. The reversal of 1101302013029 is 9203102031011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1044954172900 + 56347840129 = 1022230^2 + 237377^2 .

It is a cyclic number.

It is not a de Polignac number, because 1101302013029 - 232 = 1097007045733 is a prime.

It is a super-2 number, since 2×11013020130292 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1101302012995 and 1101302013013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1101302013829) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550651006514 + 550651006515.

It is an arithmetic number, because the mean of its divisors is an integer number (550651006515).

Almost surely, 21101302013029 is an apocalyptic number.

It is an amenable number.

1101302013029 is a deficient number, since it is larger than the sum of its proper divisors (1).

1101302013029 is an equidigital number, since it uses as much as digits as its factorization.

1101302013029 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324, while the sum is 23.

The spelling of 1101302013029 in words is "one trillion, one hundred one billion, three hundred two million, thirteen thousand, twenty-nine".