Base | Representation |
---|---|
bin | 1010000001000010101111… |
… | …0111100011101010010111 |
3 | 1102222211120010220112112012 |
4 | 2200100223313203222113 |
5 | 2420414142211144343 |
6 | 35231152255214435 |
7 | 2214444126364103 |
oct | 240205367435227 |
9 | 42884503815465 |
10 | 11013032131223 |
11 | 356666758aaa1 |
12 | 129a49621741b |
13 | 61b6a8365ac5 |
14 | 2a10682a6903 |
15 | 14171a856718 |
hex | a042bde3a97 |
11013032131223 has 2 divisors, whose sum is σ = 11013032131224. Its totient is φ = 11013032131222.
The previous prime is 11013032131219. The next prime is 11013032131243. The reversal of 11013032131223 is 32213123031011.
11013032131223 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11013032131223 - 22 = 11013032131219 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11013032131243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506516065611 + 5506516065612.
It is an arithmetic number, because the mean of its divisors is an integer number (5506516065612).
Almost surely, 211013032131223 is an apocalyptic number.
11013032131223 is a deficient number, since it is larger than the sum of its proper divisors (1).
11013032131223 is an equidigital number, since it uses as much as digits as its factorization.
11013032131223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 11013032131223 its reverse (32213123031011), we get a palindrome (43226155162234).
The spelling of 11013032131223 in words is "eleven trillion, thirteen billion, thirty-two million, one hundred thirty-one thousand, two hundred twenty-three".
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