Base | Representation |
---|---|
bin | 1010000001000011000010… |
… | …0001110111001101110111 |
3 | 1102222211202121001110101202 |
4 | 2200100300201313031313 |
5 | 2420414322221031411 |
6 | 35231204131243115 |
7 | 2214446066146412 |
oct | 240206041671567 |
9 | 42884677043352 |
10 | 11013110330231 |
11 | 35666a7741079 |
12 | 129a4b844949b |
13 | 61b6bb6154c9 |
14 | 2a1074820b79 |
15 | 14172265183b |
hex | a0430877377 |
11013110330231 has 2 divisors, whose sum is σ = 11013110330232. Its totient is φ = 11013110330230.
The previous prime is 11013110330221. The next prime is 11013110330237. The reversal of 11013110330231 is 13203301131011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11013110330231 - 214 = 11013110313847 is a prime.
It is a super-2 number, since 2×110131103302312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11013110330237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506555165115 + 5506555165116.
It is an arithmetic number, because the mean of its divisors is an integer number (5506555165116).
Almost surely, 211013110330231 is an apocalyptic number.
11013110330231 is a deficient number, since it is larger than the sum of its proper divisors (1).
11013110330231 is an equidigital number, since it uses as much as digits as its factorization.
11013110330231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 11013110330231 its reverse (13203301131011), we get a palindrome (24216411461242).
The spelling of 11013110330231 in words is "eleven trillion, thirteen billion, one hundred ten million, three hundred thirty thousand, two hundred thirty-one".
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