11013125554431 has 96 divisors (see below), whose sum is σ = 22026816023040. Its totient is φ = 5281019078400.

The previous prime is 11013125554423. The next prime is 11013125554489. The reversal of 11013125554431 is 13445552131011.

11013125554431 is a `hidden beast` number, since 1 + 1 + 0 + 1 + 31 + 2 + 55 + 544 + 31 = 666.

11013125554431 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 11013125554431 - 2³ = 11013125554423 is a prime.

It is a super-2 number, since 2×11013125554431² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11013125554411) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 15321190 + ... + 16023891.

It is an arithmetic number, because the mean of its divisors is an integer number (229446000240).

Almost surely, 2^{11013125554431} is an apocalyptic number.

11013125554431 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

11013125554431 is an abundant number, since it is smaller than the sum of its proper divisors (11013690468609).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11013125554431 is a wasteful number, since it uses less digits than its factorization.

11013125554431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31345134 (or 31345115 counting only the distinct ones).

The product of its (nonzero) digits is 36000, while the sum is 36.

Adding to 11013125554431 its reverse (13445552131011), we get a palindrome (24458677685442).

The spelling of 11013125554431 in words is "eleven trillion, thirteen billion, one hundred twenty-five million, five hundred fifty-four thousand, four hundred thirty-one".