Base | Representation |
---|---|
bin | 11001000010100111110010… |
… | …111111010110101100000100 |
3 | 112102221110012222000002200120 |
4 | 121002213302333112230010 |
5 | 103413342432240143022 |
6 | 1030121345212341540 |
7 | 32124504046643334 |
oct | 3102476277265404 |
9 | 472843188002616 |
10 | 110131333131012 |
11 | 32100488486396 |
12 | 104282347748b0 |
13 | 495b4564110bb |
14 | 1d2a5564b30c4 |
15 | caeb7e60cd5c |
hex | 6429f2fd6b04 |
110131333131012 has 12 divisors (see below), whose sum is σ = 256973110639056. Its totient is φ = 36710444377000.
The previous prime is 110131333131007. The next prime is 110131333131031. The reversal of 110131333131012 is 210131333131011.
110131333131012 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is a tau number, because it is divible by the number of its divisors (12).
It is a super-2 number, since 2×1101313331310122 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4588805547114 + ... + 4588805547137.
It is an arithmetic number, because the mean of its divisors is an integer number (21414425886588).
Almost surely, 2110131333131012 is an apocalyptic number.
110131333131012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
110131333131012 is an abundant number, since it is smaller than the sum of its proper divisors (146841777508044).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
110131333131012 is a wasteful number, since it uses less digits than its factorization.
110131333131012 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9177611094258 (or 9177611094256 counting only the distinct ones).
The product of its (nonzero) digits is 486, while the sum is 24.
Adding to 110131333131012 its reverse (210131333131011), we get a palindrome (320262666262023).
Subtracting 110131333131012 from its reverse (210131333131011), we obtain a palindrome (99999999999999).
The spelling of 110131333131012 in words is "one hundred ten trillion, one hundred thirty-one billion, three hundred thirty-three million, one hundred thirty-one thousand, twelve".
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