Base | Representation |
---|---|
bin | 10100100000110111… |
… | …10011011001110010 |
3 | 1001102112011120211222 |
4 | 22100123303121302 |
5 | 140023331022010 |
6 | 5020453505042 |
7 | 536626110044 |
oct | 122033633162 |
9 | 31375146758 |
10 | 11013142130 |
11 | 47416a4761 |
12 | 2174342182 |
13 | 1066879463 |
14 | 766931a94 |
15 | 446cd8355 |
hex | 2906f3672 |
11013142130 has 128 divisors (see below), whose sum is σ = 22126141440. Its totient is φ = 3929333760.
The previous prime is 11013142123. The next prime is 11013142169. The reversal of 11013142130 is 3124131011.
11013142130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (17).
It is a junction number, because it is equal to n+sod(n) for n = 11013142099 and 11013142108.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 57660335 + ... + 57660525.
It is an arithmetic number, because the mean of its divisors is an integer number (172860480).
Almost surely, 211013142130 is an apocalyptic number.
11013142130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11013142130 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.
11013142130 is a wasteful number, since it uses less digits than its factorization.
11013142130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 444.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 11013142130 its reverse (3124131011), we get a palindrome (14137273141).
The spelling of 11013142130 in words is "eleven billion, thirteen million, one hundred forty-two thousand, one hundred thirty".
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