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11013201101207 is a prime number
BaseRepresentation
bin1010000001000011010111…
…1100001000000110010111
31102222211222220212002202202
42200100311330020012113
52420420013440214312
635231221132555115
72214451250533004
oct240206574100627
942884886762682
1011013201101207
1135667439a9708
12129a522922a9b
1361b704377346
142a10828cc8ab
1514172a5d19c2
hexa0435f08197

11013201101207 has 2 divisors, whose sum is σ = 11013201101208. Its totient is φ = 11013201101206.

The previous prime is 11013201101173. The next prime is 11013201101263. The reversal of 11013201101207 is 70210110231011.

It is a weak prime.

It is an emirp because it is prime and its reverse (70210110231011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11013201101207 - 216 = 11013201035671 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11013201181207) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506600550603 + 5506600550604.

It is an arithmetic number, because the mean of its divisors is an integer number (5506600550604).

Almost surely, 211013201101207 is an apocalyptic number.

11013201101207 is a deficient number, since it is larger than the sum of its proper divisors (1).

11013201101207 is an equidigital number, since it uses as much as digits as its factorization.

11013201101207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 84, while the sum is 20.

Adding to 11013201101207 its reverse (70210110231011), we get a palindrome (81223311332218).

The spelling of 11013201101207 in words is "eleven trillion, thirteen billion, two hundred one million, one hundred one thousand, two hundred seven".