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1101321000151 = 6781162412771
BaseRepresentation
bin10000000001101011110…
…110001101010011010111
310220021200221202112021021
4100001223312031103113
5121021001134001101
62201535003102011
7142365522020641
oct20015366152327
93807627675237
101101321000151
11395081aa1a59
1215953a211907
137cb14686978
143b438ad3891
151d9ab93d5a1
hex1006bd8d4d7

1101321000151 has 4 divisors (see below), whose sum is σ = 1101483419704. Its totient is φ = 1101158580600.

The previous prime is 1101321000127. The next prime is 1101321000161. The reversal of 1101321000151 is 1510001231011.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1101321000151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1101321000161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81199605 + ... + 81213166.

It is an arithmetic number, because the mean of its divisors is an integer number (275370854926).

Almost surely, 21101321000151 is an apocalyptic number.

1101321000151 is a deficient number, since it is larger than the sum of its proper divisors (162419553).

1101321000151 is an equidigital number, since it uses as much as digits as its factorization.

1101321000151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 162419552.

The product of its (nonzero) digits is 30, while the sum is 16.

Adding to 1101321000151 its reverse (1510001231011), we get a palindrome (2611322231162).

The spelling of 1101321000151 in words is "one trillion, one hundred one billion, three hundred twenty-one million, one hundred fifty-one", and thus it is an aban number.

Divisors: 1 6781 162412771 1101321000151