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11013241333 is a prime number
BaseRepresentation
bin10100100000111000…
…01011100111110101
31001102112100121221011
422100130023213311
5140023342210313
65020455552221
7536630002213
oct122034134765
931375317834
1011013241333
114741762246
12217438b671
1310668b2663
14766959cb3
15446d0793d
hex29070b9f5

11013241333 has 2 divisors, whose sum is σ = 11013241334. Its totient is φ = 11013241332.

The previous prime is 11013241307. The next prime is 11013241373. The reversal of 11013241333 is 33314231011.

11013241333 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6045529009 + 4967712324 = 77753^2 + 70482^2 .

It is an emirp because it is prime and its reverse (33314231011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11013241333 - 233 = 2423306741 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11013241373) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506620666 + 5506620667.

It is an arithmetic number, because the mean of its divisors is an integer number (5506620667).

Almost surely, 211013241333 is an apocalyptic number.

It is an amenable number.

11013241333 is a deficient number, since it is larger than the sum of its proper divisors (1).

11013241333 is an equidigital number, since it uses as much as digits as its factorization.

11013241333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 11013241333 its reverse (33314231011), we get a palindrome (44327472344).

The spelling of 11013241333 in words is "eleven billion, thirteen million, two hundred forty-one thousand, three hundred thirty-three".