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11013323131997 is a prime number
BaseRepresentation
bin1010000001000011110100…
…1101101000110001011101
31102222212022102110220112122
42200100331031220301131
52420420241210210442
635231241212312325
72214454262012624
oct240207515506135
942885272426478
1011013323131997
1135667a68781aa
12129a5577726a5
1361b723732704
142a1094bb66bb
15141736188dd2
hexa043d368c5d

11013323131997 has 2 divisors, whose sum is σ = 11013323131998. Its totient is φ = 11013323131996.

The previous prime is 11013323131961. The next prime is 11013323132027. The reversal of 11013323131997 is 79913132331011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6033846919321 + 4979476212676 = 2456389^2 + 2231474^2 .

It is a cyclic number.

It is not a de Polignac number, because 11013323131997 - 216 = 11013323066461 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11013323101997) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506661565998 + 5506661565999.

It is an arithmetic number, because the mean of its divisors is an integer number (5506661565999).

Almost surely, 211013323131997 is an apocalyptic number.

It is an amenable number.

11013323131997 is a deficient number, since it is larger than the sum of its proper divisors (1).

11013323131997 is an equidigital number, since it uses as much as digits as its factorization.

11013323131997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 91854, while the sum is 44.

The spelling of 11013323131997 in words is "eleven trillion, thirteen billion, three hundred twenty-three million, one hundred thirty-one thousand, nine hundred ninety-seven".