Base | Representation |
---|---|
bin | 10100100000111110… |
… | …01100110001111111 |
3 | 1001102120211211020001 |
4 | 22100133030301333 |
5 | 140024043020021 |
6 | 5020524535131 |
7 | 536636505646 |
oct | 122037146177 |
9 | 31376754201 |
10 | 11014032511 |
11 | 4742152709 |
12 | 21746b14a7 |
13 | 1066acb801 |
14 | 766ac435d |
15 | 446e12091 |
hex | 2907ccc7f |
11014032511 has 2 divisors, whose sum is σ = 11014032512. Its totient is φ = 11014032510.
The previous prime is 11014032487. The next prime is 11014032529. The reversal of 11014032511 is 11523041011.
It is a strong prime.
It is an emirp because it is prime and its reverse (11523041011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11014032511 - 25 = 11014032479 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11014032541) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5507016255 + 5507016256.
It is an arithmetic number, because the mean of its divisors is an integer number (5507016256).
Almost surely, 211014032511 is an apocalyptic number.
11014032511 is a deficient number, since it is larger than the sum of its proper divisors (1).
11014032511 is an equidigital number, since it uses as much as digits as its factorization.
11014032511 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120, while the sum is 19.
Adding to 11014032511 its reverse (11523041011), we get a palindrome (22537073522).
The spelling of 11014032511 in words is "eleven billion, fourteen million, thirty-two thousand, five hundred eleven".
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