Base | Representation |
---|---|
bin | 10100100000111110… |
… | …01101011011100101 |
3 | 1001102120211221212122 |
4 | 22100133031123211 |
5 | 140024043111143 |
6 | 5020524555325 |
7 | 536636516501 |
oct | 122037153345 |
9 | 31376757778 |
10 | 11014035173 |
11 | 4742154709 |
12 | 21746b2b45 |
13 | 1066acca9b |
14 | 766ac5301 |
15 | 446e12c68 |
hex | 2907cd6e5 |
11014035173 has 2 divisors, whose sum is σ = 11014035174. Its totient is φ = 11014035172.
The previous prime is 11014035119. The next prime is 11014035223. The reversal of 11014035173 is 37153041011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8585319649 + 2428715524 = 92657^2 + 49282^2 .
It is a cyclic number.
It is not a de Polignac number, because 11014035173 - 222 = 11009840869 is a prime.
It is a super-2 number, since 2×110140351732 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11014035103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5507017586 + 5507017587.
It is an arithmetic number, because the mean of its divisors is an integer number (5507017587).
Almost surely, 211014035173 is an apocalyptic number.
It is an amenable number.
11014035173 is a deficient number, since it is larger than the sum of its proper divisors (1).
11014035173 is an equidigital number, since it uses as much as digits as its factorization.
11014035173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1260, while the sum is 26.
Adding to 11014035173 its reverse (37153041011), we get a palindrome (48167076184).
The spelling of 11014035173 in words is "eleven billion, fourteen million, thirty-five thousand, one hundred seventy-three".
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